algebra

Mary has $4.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and forty-seven more nickels than dimes, how many coins of each type does she have?

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  1. number of quarters --- x
    number of dimes ---- 2x
    number of nickels ---- 2x+47

    25x + (10)(2x) + 5(2x+47) = 400
    solve for x, then sub into my definitions

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  2. i zunno

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