How do i find the perimeter of a triangle with variables?
one side is 2(q^2 - 3q), the second side is q + 10 and the third side is q^2.
how do i add all of these sides
2(q^2-3q) = 2q^2-6q
So, you want to add up
2q^2-6q+q+10+q^2
Keep like powers together, and you end up with
(2+1)q^2 + (=6+1)q + 10
3q^2-5q+10
To find the perimeter of a triangle with variables, you need to add up the lengths of all its sides. In this case, the triangle has three sides:
1. The first side: 2(q^2 - 3q)
2. The second side: q + 10
3. The third side: q^2
To calculate the perimeter, you add up these three sides:
Perimeter = 2(q^2 - 3q) + (q + 10) + q^2
Let's simplify this equation step by step.
First, distribute the 2 to the terms within the parentheses:
Perimeter = 2q^2 - 6q + q + 10 + q^2
Next, combine the like terms:
Perimeter = 2q^2 + q^2 - 6q + q + 10
Combine the similar terms further:
Perimeter = 3q^2 - 5q + 10
So, the perimeter of the triangle with the given sides is 3q^2 - 5q + 10.