I need help with this problem:
Let f(x)= sqrt(x-3) and g(x)=(x^2)+1
a. Compute g(f(x))
b. State the domain of g(f(x)) in interval notation.
I got x-2 for a, but i do not understand b. Help please
a. g(f(x))= (x-3)+2 = x-2
The domain of g(f(x)) is all real numbers, but x must exceed 3 if f(x) is only to be defined for real numbers. So this question could have different interprations