1. A voltage of 13 V is applied across the ends of a piece of copper wire 8 cm long. The mass of an electron is 9.11 × 10−31 kg and its charge is 1.6 × 10−19 C.

What is the magnitude of the electron’s acceleration?
Answer in units of m/s2.

2. After traveling 3 × 10−8 m, if it does not collide with a copper ion over this distance, what is the kinetic energy of the electron? Answer in units of eV.

1. To find the magnitude of the electron's acceleration, we can use the equation for acceleration:

acceleration (a) = voltage (V) / length (L)

In this case, the voltage across the copper wire is given as 13 V and the length of the wire is given as 8 cm (or 0.08 m). Plugging these values into the equation, we get:

a = 13 V / 0.08 m = 162.5 m/s^2

Therefore, the magnitude of the electron's acceleration is 162.5 m/s^2.

2. To find the kinetic energy of the electron after traveling a certain distance, we can use the equation for kinetic energy:

kinetic energy (KE) = 0.5 * mass * velocity^2

However, we are given the distance traveled instead of the velocity. We know that distance (d) is equal to velocity (v) multiplied by time (t):

d = v * t

Solving for velocity (v), we get:

v = d / t

In this case, the distance traveled by the electron is given as 3 × 10^-8 m. However, we don't have information about the time taken by the electron. Without knowing the time, we can't determine the velocity of the electron.

Therefore, we cannot calculate the kinetic energy of the electron without additional information.