1) The force of gravity on the moon is 1/6 the force of gravity on earth. If you had a 1 kg box of cereal on earth which had a weight of 2.4 N, what would its mass be on the moon? why?
2) what is the volume of a textbook with dimensions 21.3 cm, 27.5 cm, 2.9 cm?
please help me, how could i get the answer for these questions.
Sure! I can help you find the answers to both of these questions.
1) To find the mass of the cereal box on the moon, we need to understand the relationship between weight, mass, and gravity. Weight is the force of gravity acting on an object, and it is given by the formula W = m × g, where W is the weight, m is the mass, and g is the acceleration due to gravity.
On Earth, the weight of the 1 kg cereal box is given as 2.4 N. Since the force of gravity on the moon is 1/6 of that on Earth, we can calculate the weight on the moon by dividing the weight on Earth by 6. So, the weight of the cereal box on the moon would be 2.4 N ÷ 6 = 0.4 N.
Now, to find the mass on the moon, we rearrange the formula W = m × g to solve for mass, m = W ÷ g. Since the weight on the moon is 0.4 N, and the acceleration due to gravity on the moon is 1/6 of that on Earth, we can calculate the mass on the moon as 0.4 N ÷ (9.8 m/s^2 ÷ 6) = 0.4 N ÷ 1.63 m/s^2 ≈ 0.25 kg.
So, the mass of the cereal box on the moon would be approximately 0.25 kg.
2) To calculate the volume of the textbook, we can use the formula V = l × w × h, where V is the volume, l is the length, w is the width, and h is the height.
Given the dimensions of the textbook as 21.3 cm, 27.5 cm, and 2.9 cm for length, width, and height respectively, we can substitute these values into the formula to find the volume.
Using the formula, the volume of the textbook would be V = 21.3 cm × 27.5 cm × 2.9 cm = 1650.375 cm^3.
So, the volume of the textbook is approximately 1650.375 cm^3.
To solve these types of questions in general, it is important to understand the relevant formulas and apply them correctly using the given information.