A stone with a mass of 6kg is thrown vertically upwards from the top of a building 35m high with a starting velocity of 20m/s. The time it will take to reach its maximum height
V = Vo + g*t
V = 0
Vo = 20 m/s.
g = -9.8 m/s^2
Solve for t.
To find the time it will take for the stone to reach its maximum height, we can use the kinematic equation for vertical motion:
vf = vi + at
Where:
- vf is the final velocity (which will be zero when the stone reaches its maximum height)
- vi is the initial velocity (20 m/s in this case)
- a is the acceleration (due to gravity, which is approximately -9.8 m/s^2)
- t is the time
In this case, we want to find the time it takes for the stone to reach its maximum height, so we can set vf = 0:
0 = 20 m/s - 9.8 m/s^2 * t
Simplifying the equation, we get:
9.8 m/s^2 * t = 20 m/s
To solve for time, we divide both sides of the equation by 9.8 m/s^2:
t = 20 m/s / 9.8 m/s^2
t ≈ 2.04 seconds
Therefore, it will take approximately 2.04 seconds for the stone to reach its maximum height.