REALLY NEED HELP WITH THIS PLEASE.
One gram of palladium has 5.66×10^21 atoms, and each palladium atom has 46 electrons. How many electrons are contained in 7.00g of palladium? The elemental charge is1.6×10^−19C. Answer in units of electrons.
The answer is 1.82252x10^24 for Part A. i need help with part B.
b)What is the total charge of these electrons? Answer in units of C.
I Did 1.82252x10^24 x 1.6x10^-19 and i got 291603.2 but it's wrong. can someone help me with this part?
See previous post: Sun, 2-8-15, 8:14 PM.
To find the total charge of the electrons in 7.00g of palladium, you need to multiply the number of electrons by the elemental charge. Let's break down the steps to calculate this:
1. Convert the given mass of palladium from grams to moles.
To do this, we need the molar mass of palladium. The molar mass of palladium is approximately 106.42 g/mol. Divide the given mass (7.00g) by the molar mass to get the number of moles:
7.00g / 106.42 g/mol = 0.06586 mol
2. Calculate the number of atoms in 7.00g of palladium.
Since we know that 1 gram of palladium has 5.66×10^21 atoms, we can multiply the number of moles by Avogadro's number (6.022×10^23 atoms/mol) to find the number of atoms:
0.06586 mol × 6.022×10^23 atoms/mol = 3.964x10^22 atoms
3. Determine the number of electrons in 7.00g of palladium.
Since each palladium atom has 46 electrons, multiply the number of atoms by 46:
3.964x10^22 atoms × 46 electrons/atom = 1.824x10^24 electrons
So, the answer to part A is indeed 1.824x10^24 electrons.
4. Calculate the total charge of the electrons.
To find the total charge, multiply the number of electrons by the elemental charge:
1.824x10^24 electrons × 1.6×10^−19 C/electron = 2.9184x10^5 C
The answer to part B is 2.9184x10^5 Coulombs (C), not 291603.2 C as you calculated. Make sure to check your arithmetic and properly account for the given values and units in order to obtain the correct answer.