One gram of palladium has 5.66×10^21 atoms, and each palladium atom has 46 electrons. How many electrons are contained in 7.00g of palladium? The elemental charge is1.6×10^−19C. Answer in units of electrons.
The answer is 1.82252x10^24 for Part A. i need help with part B.
b)What is the total charge of these electrons? Answer in units of C.
I Did 1.82252x10^24 x 1.6x10^-19 and i got 291603.2 but it's wrong. can someone help me with this part?
issa negative
Part B. total charge=numberelectrons*charge/electron
1.82253E24 x 1.6E-19 C= your answer. Wondering if it should be in scientific notation, ie, 2.916E5 C
no the answer is incorrect. im so confused @bob
To determine the total charge of the electrons in 7.00g of palladium, we first need to calculate the total number of electrons in 7.00g of palladium. Given that one gram of palladium has 5.66×10^21 atoms and each palladium atom has 46 electrons, we can set up the following equation:
Number of atoms in 7.00g of palladium = 5.66×10^21 atoms/g × 7.00g = 3.962×10^22 atoms
Number of electrons in 7.00g of palladium = Number of atoms × Number of electrons per atom = 3.962×10^22 atoms × 46 electrons/atom = 1.82252×10^24 electrons
Now, to calculate the total charge of these electrons, we multiply the number of electrons by the elemental charge, which is 1.6×10^−19 C:
Total charge of electrons = Number of electrons × Elemental charge = 1.82252×10^24 electrons × 1.6×10^−19 C/electron
Performing the multiplication, we get:
Total charge of electrons = 2.916032×10^5 C
Therefore, the total charge of the electrons in 7.00g of palladium is 2.916032×10^5 C.