Write two hydrolysis reactions for Cu^2+ reacting with water in each step to form CuOH^+ and Cu(OH)2. The hydrolysis constants for the two reactions are:

log kh1 = -7.7 and log Kh2 = -6.1

Cu^2+ + 2HOH ==> Cu(OH)^+ + H3O^+

Cu(OH)^+ + 2HOH ==> Cu(OH)2 + H3O^+
Why do I need the log K for the equatiions?