A cash register contains only five dollar and fifty dollar bills. It contains four times as many five dollar bills as fifty dollar bills and the total amount of money in the cash register is $2,870. How many fifty dollar bills are in the cash register?
41
Let's assume the number of fifty dollar bills as 'x'.
Therefore, the number of five dollar bills will be 4 * x.
The value of each fifty dollar bill is $50, so the total value of the fifty dollar bills will be 50 * x.
The value of each five dollar bill is $5, so the total value of the five dollar bills will be 5 * (4 * x).
According to the given condition, the total amount of money in the cash register is $2,870, which can be written as an equation:
50x + 5(4x) = 2870
Now let's solve the equation to find the value of 'x'.
50x + 20x = 2870
70x = 2870
x = 41
Therefore, there are 41 fifty dollar bills in the cash register.
To solve this problem, we need to set up a system of equations based on the given information.
Let's assume that there are x fifty dollar bills in the cash register. Since there are four times as many five dollar bills as fifty dollar bills, there are 4x five dollar bills.
Now, we can calculate the total value of the money in the cash register:
Total value = (Value of fifty dollar bills) + (Value of five dollar bills)
Value of fifty dollar bills = x * $50 = 50x
Value of five dollar bills = 4x * $5 = 20x
According to the problem, the total amount of money in the cash register is $2,870, so we can set up the equation:
50x + 20x = 2870
Combining like terms:
70x = 2870
Dividing both sides by 70:
x = 2870 / 70
Calculating x:
x ≈ 41
Therefore, there are approximately 41 fifty dollar bills in the cash register.
If there are x at $5 and y at $50, then we are told that
x = 4y
5x+50y = 2870
So, now just solve for y.