A math class has a total of 47 students. the number of females is 17 less than the numberof males. how many males and how many females are in class?
m = males
m + m - 17 = 47
2m = 64
m = ?
26
Let's assume the number of males in the math class is "x".
According to the given information, the number of females is 17 less than the number of males. Therefore, the number of females is "x - 17".
We know that the total number of students in the class is 47. So, the equation is:
x + (x - 17) = 47
Combining like terms, the equation becomes:
2x - 17 = 47
Adding 17 to both sides, the equation becomes:
2x = 64
Dividing both sides by 2, we find:
x = 32
So, there are 32 males in the math class.
Substituting the value of x back into the equation x - 17, we find:
32 - 17 = 15
Therefore, there are 15 females in the math class.
To solve this problem, we can set up a system of equations.
Let's assume the number of males is represented by 'x'. The number of females can then be represented by 'x - 17'.
We know that the total number of students in the class is 47. So, we can set up the equation:
x + (x - 17) = 47
Combining like terms, we get:
2x - 17 = 47
Next, we can add 17 to both sides of the equation:
2x = 47 + 17
Simplifying further, we have:
2x = 64
Finally, we divide both sides of the equation by 2 to solve for 'x':
x = 32
So, there are 32 males in the class.
To find the number of females, we substitute 'x' back into our equation:
x - 17 = 32 - 17 = 15
Therefore, there are 15 females in the class.
In conclusion, there are 32 males and 15 females in the math class.