Two angles of a quadrilateral measure 130° and 20°. The other two angles are in a ratio of 5:16. What are the measures of those two angles?
did you get this from IXL?
i got this from IXL and this is giving me problems
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i also know that in IXL
let the smaller of the unknown angles be 5x and the larger of the two be 16x
so 130+20+5x+16x = 360
21x = 210
x = 10
so the two missing angles are 50° and 160°
check: 50+160+130+20 = 360
50:160 = 5 : 16
Since the angles are in a ratio of 5:6, they have measures of 5n and 6n. Set the sum of the angle measures equal to 360° and solve.
70° + 180° + 5n + 6n = 360°
250° + 11n = 360° Combine like terms
11n = 360° − 250° Subtract 250° from both sides
11n = 110° Simplify
n = 10° Divide both sides by 11
Now plug in n = 10° to find the measures of the angles.
5n and 6n
5 × 10° and 6 × 10°
50° and 60°
So, the measures of the two angles are 50° and 60°.