An original samplemof an unknown potassium chloride/potassium cholate mixture weighed 1.042g before heating and 0.943g after heating. How many grams of oxygen were released?
2KClO3 ==> 2KCl + 3O2
Loss in mass = mass O2 lost = 1.042-0.943 = 0.099
mols O2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols O2 to mols KClO3.
Then convert mols KClO3 to grams KClO3 with g = mols x molar mass.
To determine the number of grams of oxygen released, we first need to calculate the change in mass of the sample before and after heating. The difference between these two masses will correspond to the amount of oxygen released.
Given:
Initial mass (before heating) = 1.042 g
Final mass (after heating) = 0.943 g
Change in mass = Initial mass - Final mass
Change in mass = 1.042 g - 0.943 g
Change in mass = 0.099 g
Now, this change in mass corresponds to the oxygen released. Since we are assuming the entire change in mass is due to oxygen, we can conclude that 0.099 grams of oxygen were released during the heating process.