Calculus

Find the anti-derivative of the integral
[3sqrt(x)(2x^2-4)]dx

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  1. ∫3√x (2x^2-4) dx
    If we let
    u = √x
    du = 1/2√x dx
    x = u^2

    and we have
    ∫3√x (2x^2-4) dx
    ∫6x (2x^2-4) dx/2√x
    ∫6u^2(2u^4-4) du
    and that's just power stuff.

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    posted by Steve

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