Calculate the amount of heat required to heat a50kg sample of ethanol from 13.0∘C to 18.0∘C Specific heat capacity of ethanol is 2.42 J/g∘C.?

Please help

q = mass ethanol x specific heat ethanol x (Tfinal-Tinitial)

To calculate the amount of heat required to heat a sample of ethanol, we can use the formula:

Q = m * c * ΔT

Where:
Q is the amount of heat required (in joules)
m is the mass of the sample (in grams)
c is the specific heat capacity of ethanol (in J/g∘C)
ΔT is the change in temperature (in ∘C)

First, we need to convert the mass of the sample from kilograms to grams. Since 1 kilogram is equal to 1000 grams, the mass of the sample is:

m = 50 kg * 1000 g/kg
m = 50000 g

Now, we can substitute the values into the formula:

Q = 50000 g * 2.42 J/g∘C * (18.0∘C - 13.0∘C)

Simplifying the expression inside the parentheses:

Q = 50000 g * 2.42 J/g∘C * 5.0∘C

Q = 605000 J

Therefore, the amount of heat required to heat a 50 kg sample of ethanol from 13.0∘C to 18.0∘C is 605,000 Joules.