Determine whether the polygons are similar.
ABCD with vertices A(–5, 4), B(–2, 4), C(–2, 2), D(–5, 2)
and EFGH with vertices E(–2, 0), F(4, 0), G(4, –6), H(–2, –6)
They aren't similar, right?
http://www.jiskha.com/display.cgi?id=1422926711
How can I tell without seeing your calculations ?
Determine whether the polygons with the given vertices are similar. Support your
answer by describing a transformation.
7.
L
(1,
-
4),
M
(1,
-
9),
N
(5,
-
2),
O
(9,
-
5)
8.
W
(
-
4, 2),
X
(
-
4, 6),
Y
(6, 2),
Z
(6, 6)
P
(2, 5),
Q
(2,
-
5),
R
(10, 9),
S
(18, 3)
D
(
-
2, 1),
E
(
-
8, 12),
F
(3, 10),
G
(3, 3
To determine whether two polygons are similar, we need to examine if their corresponding angles are congruent and if their corresponding sides are proportional.
First, let's identify the corresponding sides:
For ABCD, the lengths of the sides are:
AB = 3
BC = 2
CD = 3
AD = 2
For EFGH, the lengths of the sides are:
EF = 6
FG = 6
GH = 6
HE = 6
As we can see, the corresponding sides of ABCD and EFGH are not proportional. The sides AB and EF have different lengths, BC and FG have different lengths, CD and GH have different lengths, and AD and HE have different lengths.
Since the corresponding sides are not proportional, we can conclude that the polygons ABCD and EFGH are not similar.
So, you are correct. They are not similar.