A solid of relative density 1.25 is found to weigh 12 g in water.find its weight in air.
We know that weight in air÷weight in air -weight in water=relative density
Substituting values we get 60g as answer take weight in air as x
Thus it would be x/x-12=1.25
To find the weight of the solid in air, we need to understand the concept of relative density and how it relates to buoyancy.
Relative density (also known as specific gravity) is the ratio of the density of a substance to the density of a reference substance, typically water. In this case, the relative density of the solid is given as 1.25, which means it is 1.25 times denser than water.
When an object is submerged in a fluid (in this case, water), it experiences an upward force called buoyancy. This buoyant force is equal to the weight of the fluid displaced by the object. If the object's weight in water is less than its weight in air, it means the buoyant force is partially offsetting its weight.
To find the weight of the solid in air, we'll follow these steps:
1. Calculate the weight of the water displaced by the solid.
2. Calculate the weight of the solid in water.
3. Subtract the weight of the water displaced from the weight of the solid in water.
Step 1: Calculate the weight of the water displaced by the solid.
Density of water = 1 g/cm³ (since density is mass/volume, and water has a mass of 1 g for every cm³)
Volume of water displaced = mass of the solid / density of water
Volume of water displaced = 12 g / 1 g/cm³ = 12 cm³
Step 2: Calculate the weight of the solid in water.
Weight of the solid in water = weight of the solid in air - weight of the water displaced
Weight of the solid in water = 12 g
Step 3: Calculate the weight of the solid in air.
Weight of the solid in air = weight of the solid in water + weight of the water displaced
Weight of the solid in air = 12 g + 12 g = 24 g
Therefore, the weight of the solid in air is 24 grams.