chm

An aqueous solution that is 30.0 percent sulfuric acid (H2SO4) by mass has a density of 1.105 g/mL. Determine the molarity of the solution.

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  1. water is 1 g/mL
    so we have 0.105 g of H2SO4 per mL
    How many mols is that
    H2 = 2 g/mol
    S = 32 g/mol
    4 O = 64 g/mol
    total = 98 g/mol
    .105/98 = .0011 mol /mL which is
    1.1 mol/Liter

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  2. I disagree with Damon's answer.
    1.105 g/mL x 1000 mL x 0.30 x (1 mol/98g) = 3.4 M

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  3. I might make that 3.38 M to 3 s.f.

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