Bob Pursley,

With regards to a question posted by john on Tuesday, January 30, 2007 at 6:14am:

How is it that you used 650 degrees C + 273 K when the question asks to presume it stayed gaseous down to 0 degrees C and to use this 0 degrees C for the answer?

Don't mean to question a better judgement than mine but should it not be 0 degrees C + 273 = 273 K?

Thanks in advance

Bob P is on-line right now BUT not at the computer so I will take the liberty of answering for him. I went back and found the original question and answers. He used PV=nRT twice. When he used PV=nRT the FIRST time, that was to find n, the number of moles. He used the conditions at that T and P which is as it should be. The original P and T were given so n could be calculated. In the SECOND calculation, where we are solving for V, he did use 760 mm Hg P and 273 (actually he made a typo and typed 274). I hope this answers your concerns.

Here is a periodic table on the web. Look up element number 116. What chemistry we know about that is there; also, it should have similar chemical properties to S, Se, Te, Po, etc.
http://www.webelements.com/

Hello,

It seems that you have a question regarding the use of temperature values in a calculation. The original question asked how to calculate the volume (V) given the pressure (P), temperature (T), and number of moles (n) of a gas. The initial temperature given in the question was 650 degrees C.

To use the ideal gas law equation PV = nRT, we need to convert the temperature to Kelvin (K) because temperature is always measured in Kelvin in gas calculations. To convert Celsius to Kelvin, we add 273.15 to the Celsius value. In this case, the conversion would be 650 degrees C + 273.15 = 923.15 K.

However, in the follow-up question, the request was made to presume that the gas stayed gaseous down to 0 degrees Celsius. Therefore, the temperature to be used in the calculation should be 0 degrees Celsius. To convert this to Kelvin, we add 273, giving us 273 K.

So, for the calculation in question, it should indeed be 0 degrees Celsius + 273 = 273 K. My apologies for any confusion that may have been caused.

Regarding your request for information on element number 116, I would recommend visiting the website http://www.webelements.com/. This website provides a periodic table with detailed information about each element, including chemistry and similar chemical properties.

I hope this clarifies the points of confusion and provides the information you were looking for. Let me know if there's anything else I can assist you with!