PHYS1111_HMWK02_Vectors_and_2DKinematics » Eddie the Eagle
Eddie the Eagle, British Olympic ski jumper, is attempting his most mediocre jump yet. After leaving the end of the ski ramp, he lands downhill at a point that is displaced 62.2 m horizontally from the edge of the ramp. His velocity just before landing is 29.0 m/s and points in a direction 39.0 below the horizontal. Neglect any effects due to air resistance or lift.
What was the magnitude of Eddie's initial velocity as he left the ramp?
Determine Eddie's initial direction of motion as he left the ramp, measured relative to the horizontal.
Calculate the height of the ramp's edge relative to where Eddie landed.
See Related Questions: Fri, 1-31-14, 10:23 PM.
To find the magnitude of Eddie's initial velocity as he left the ramp, we can use the horizontal displacement and the time it takes him to reach the landing point.
First, let's calculate the time it takes Eddie to reach the landing point. Since we're neglecting air resistance or lift, the horizontal velocity remains constant throughout the motion. We can use the horizontal displacement and horizontal velocity to find the time:
time = horizontal displacement / horizontal velocity
time = 62.2 m / (29.0 m/s * cos(39.0°))
Now, we can calculate the time using the given values and calculate the magnitude of Eddie's initial velocity using the vertical displacement.
To find the initial direction of motion as he left the ramp, we need to determine the angle between the initial velocity and the horizontal.
Finally, to calculate the height of the ramp's edge relative to where Eddie landed, we can use the equation for vertical displacement in projectile motion:
vertical displacement = (initial velocity * sinθ * time) - (0.5 * gravitational acceleration * time^2)
Substituting the values we have, we can find the height of the ramp's edge relative to where Eddie landed.