Hello please help me with another question!
-
One fruit fly is heterozygous for long wings, and another fruit fly is homozygous for short wings. Long wings are dominant to short wings. Using a punnett square, find out what percent of the offspring are expected to have short wings.
Let's let L be long wings; s for short wings.
So we have Ls and ss
So the combinations are
Ls; Ls; ss and ss.
The two Ls will be long and the ss will be short wings which looks like 50% to me.
To find out the percentage of offspring that are expected to have short wings, we can use a Punnett square, which is a grid used to predict the possible genotypes and phenotypes of offspring from a cross between two individuals.
In this case, we have one fruit fly that is heterozygous for long wings (Ll) and another fruit fly that is homozygous for short wings (ll). Long wings (L) are dominant to short wings (l).
To create a Punnett square, we write down the genotypes of the two parents on the margins of the square. Since the first fly is heterozygous for long wings (Ll), we write L on one side of the square and l on the other side. Since the second fly is homozygous for short wings (ll), we write l on both sides.
```
| L | l |
---------------
L | LL | Ll |
---------------
l | Ll | ll |
```
Now, we can read the possible genotypes and phenotypes of the offspring from the Punnett square.
- LL: Offspring with genotype LL will have long wings.
- Ll: Offspring with genotype Ll will have long wings.
- ll: Offspring with genotype ll will have short wings.
The Punnett square shows that there are two possible genotypes for short wings: Ll and ll. Since ll is the only genotype that results in short wings, it means that 50% (or half) of the offspring are expected to have short wings.
Therefore, the percentage of offspring expected to have short wings is 50%.