A pizza chef made and sold a total of 100 pizzas that were either cheese or pepperoni. The cheese pizza's were $9 each and the pepperoni pizzas sold for $11 each. If the total receipts were $1026, how many pepperoni pizzas did he sell?
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Tom curry apple jacks
To solve this problem, we will use a system of equations.
Let's assume that the number of cheese pizzas sold is represented by the variable "C," and the number of pepperoni pizzas sold is represented by the variable "P."
We are given two pieces of information:
1. The total number of pizzas sold is 100. So, we can write the equation: C + P = 100.
2. The total receipts from selling the pizzas amount to $1026. The cost of each cheese pizza is $9 and the cost of each pepperoni pizza is $11. So, we can write the equation: 9C + 11P = 1026.
Now, we have a system of two equations:
C + P = 100 ...(1)
9C + 11P = 1026 ...(2)
We can solve this system of equations using various methods, such as substitution or elimination. Let's use the substitution method here.
From equation (1), we can express C in terms of P:
C = 100 - P ...(3)
Now substitute equation (3) into equation (2):
9(100 - P) + 11P = 1026
Simplifying:
900 - 9P + 11P = 1026
2P = 126
P = 63
Therefore, the pizza chef sold 63 pepperoni pizzas.
This is my work: I don't know if its right...
x-y=100
9x+11y=1026
9(x-y=100
---------
9x-9y=900
9x+11y=1026
___________
2y=1926 1926/2= 963
y=963
He sold about 87 pizzas?