suppose a male mouse is Bb and a female is bb. What percent of the mice offspring from these two mice would you expect to have black fur?
B b
b Bb bb
b Bb bb
I would say 50%, Hope I helped!
Thank you so much!
To determine the percent of mice offspring expected to have black fur, we need to understand the concepts of genetic inheritance and Punnett squares.
In this case, the male mouse genotype is Bb, and the female mouse genotype is bb. The letter "B" represents the dominant allele for black fur, and "b" represents the recessive allele for brown fur.
To predict the probability of black fur in the offspring, we can use a Punnett square. A Punnett square is a grid that allows us to visualize the possible combinations of alleles from both parents.
In this scenario:
Male mouse (Bb):
- The male mouse has one dominant allele (B) and one recessive allele (b).
Female mouse (bb):
- The female mouse has two recessive alleles (bb).
To create the Punnett square, we will place the alleles of the male mouse (Bb) on the top and the alleles of the female mouse (bb) on the left side of the square:
b b
-------------------
B | Bb Bb
b | bb bb
In the Punnett square, each box represents a potential combination of alleles that can occur in the offspring.
From the Punnett square, we can see that:
- Out of the four possible combinations, two have black fur (Bb), and two have brown fur (bb).
- Therefore, there is a 50% chance that the offspring will have black fur, and a 50% chance they will have brown fur.
Thus, we would expect that 50% of the offspring from these two mice would have black fur.