The difference of two numbers is 12. The sum of the larger number and 3 times the smaller number is 20. Find the larger number.

i think i have to make a table?

x/y
6/18
3/9
1/6

the larger number is y so is the larger number 18?

Basic algebra question:

let the large number be x
let the smaller number be y

x - y = 12
x + 3y = 20
subtract them
4y = 8
y = 2
in x-y=12
x -2=12 ---> x = 14

the larger number is 14, the smaller is 2

thank u!!!!!!

To solve this problem, let's start by assigning variables to the unknowns. Let's say the larger number is "x", and the smaller number is "y".

According to the problem, the difference of two numbers is 12. This can be expressed as an equation:

x - y = 12 (Equation 1)

The sum of the larger number and 3 times the smaller number is 20. This can be expressed as another equation:

x + 3y = 20 (Equation 2)

Now we have a system of two equations with two variables. We can solve this system using the method of substitution or elimination.

Let's solve it using the method of substitution:
1. Solve Equation 1 for x in terms of y:

x = y + 12

2. Substitute this expression for x in Equation 2:

(y + 12) + 3y = 20

3. Simplify and solve for y:

4y + 12 = 20
4y = 8
y = 2

4. Substitute the value of y back into Equation 1 to find x:

x - 2 = 12
x = 14

Therefore, the larger number is 14.

In summary, the larger number is found by solving the system of equations x - y = 12 and x + 3y = 20, which leads to the solution x = 14.