Estimate the rate of the reaction,
H2SeO3 + 6I- + 4H+ Se + 2I3- + 3H2O
given that the rate law for the reaction at 0°C is
rate = (5.0 × 10^5 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2
The reactant concentrations are [H2SeO3] = 1.5 × 10^-2 M, [I-] = 2.4 × 10^-3 M, [H+] = 1.5 × 10^-3 M.
My answer:
Rate = (5.0 × 10^5 L5mol-5s-1)(1.5 × 10^-2 M) (2.4 × 10^-3 M)^3 (1.5 × 10^-3 M)^2
Rate = 2.33 x 10^-10
rate if reaction =12
Wow, that's one speedy reaction! It's so fast that it's almost like the molecules are on a roller coaster ride. With a rate of 2.33 x 10^-10, it's like they're zooming through the reaction at lightning speed. Just make sure their safety belts are securely fastened!
Your calculation is correct, but there seems to be an error in notation regarding the units. The unit "L5mol-5s-1" is not a standard unit for rate, and it seems like there might be a mistake in the given rate law or a misinterpretation in understanding it.
To estimate the rate of the reaction, you would need to substitute the given concentrations of the reactants into the rate law equation. However, since the rate law equation provided seems to have incorrect units, it is difficult to determine the exact rate of the reaction.
If you have any further information or clarification about the rate law equation, please provide it, and I will be happy to assist you further.
To estimate the rate of the reaction, you need to use the rate law equation given. The rate law equation shows how the rate of the reaction is related to the concentrations of the reactants.
In this case, the rate law equation is:
rate = (5.0 × 10^5 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2
To estimate the rate, you need to substitute the given concentrations of the reactants into the rate law equation.
The given concentrations are:
[H2SeO3] = 1.5 × 10^-2 M
[I-] = 2.4 × 10^-3 M
[H+] = 1.5 × 10^-3 M
Substituting these values into the rate law equation:
rate = (5.0 × 10^5 L5mol-5s-1)(1.5 × 10^-2 M) (2.4 × 10^-3 M)^3 (1.5 × 10^-3 M)^2
Evaluating this expression will give you the estimated rate of the reaction.