Water is lifted from a well of depth 50m. If mass of water is 20kg and that of the rope is 0.2kg per metre the amount of work done is

12250J

To calculate the amount of work done, we can use the formula:

Work = Force × Distance

First, let's calculate the force required to lift the water.

The force needed to lift an object is equal to its weight. The weight of an object can be calculated using the formula:

Weight = Mass × Gravity

Where:
Mass = 20 kg (mass of water)
Gravity = 9.8 m/s^2 (acceleration due to gravity)

Weight = 20 kg × 9.8 m/s^2
Weight = 196 N (Newtons)

Now, we need to calculate the distance over which the force is applied.

The distance is the depth of the well, which is given as 50 meters.

Now, let's calculate the work done:

Work = Force × Distance
Work = 196 N × 50 m
Work = 9,800 J (Joules)

Therefore, the amount of work done to lift the water from a depth of 50 meters is 9,800 Joules.

To calculate the amount of work done to lift the water from the well, we need to understand the concept of work done and apply the appropriate formulas.

Work done (W) is equal to the force applied (F) multiplied by the distance over which the force is applied (d). Mathematically, it can be represented as:

W = F x d

In this case, the force applied to lift the water comes from the combined mass of the water and the rope. The force is given by the equation:

F = mass x acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Let's calculate the force:

F_water = mass_water x acceleration due to gravity
= 20 kg x 9.8 m/s^2
= 196 N

The mass of the rope per meter is given as 0.2 kg/m. Since the total length of the rope is equal to the depth of the well, which is 50 m, we can calculate the total mass of the rope:

mass_rope = mass per meter x length
= 0.2 kg/m x 50 m
= 10 kg

Now, let's calculate the total force:

F_total = F_water + F_rope
= 196 N + mass_rope x acceleration due to gravity
= 196 N + 10 kg x 9.8 m/s^2
= 196 N + 98 N
= 294 N

Finally, let's calculate the work done:

W = F_total x d
= 294 N x 50 m
= 14,700 J

Therefore, the amount of work done to lift the water from the well is 14,700 Joules (J).

12250