Samuel, Elis and David sell newspapers. One day David sold 20 newspapers more than Elis who sold 10 newspapers more than Samuel. The total number of newspapers they sold that day was 140. If Elis sold y newspapers, write the equations can be used to find the number of newspapers sold by Elis?
Elis = y
Samuel = Elis - 10
David = Elis + 20
Total = 140
See if you can find y now.
Although looking at it it's not an whole number which is strange..
Elis --- y
Samuel --- y-10
David --- y+20
y+y-10+y+20 = 140
3y = 130
y = 130/3 = 43 1/3 newspapers ????
Something is rather bogus about your question.
Notice mathematically my answer is correct:
Elis sold 43 1/3
Samuel sold 33 1/3
David sold 63 1/3
43 1/3 + 33 1/3 + 63 1/3 = 140
To find the number of newspapers sold by Elis, let's assume that Samuel sold x newspapers.
According to the given information, David sold 20 newspapers more than Elis. So, the number of newspapers sold by David would be y + 20.
Also, Elis sold 10 newspapers more than Samuel. Therefore, the number of newspapers sold by Elis would be x + 10.
Together, Samuel, Elis, and David sold a total of 140 newspapers.
So, the equation can be written as:
x + (x + 10) + (y + 20) = 140
Simplifying the equation further will give you the equation to find the number of newspapers sold by Elis.