The radius of a cylinder is 3x-2cm. The height of the cylinder is x+3cm. What is the surface area of the cylinder?
the surface area is the two circular bases, plus the curved sides.
a = πr^2 + πr^2 + 2πrh
= 2πr(r+h)
= 2π(3x-2)(3x-2+x+3)
= 2π(3x-2)(4x+1)
I need help with this problem too.
Never Mind I got the Answer and They are:
1. A
2. D
3. B
4. D
5. C
Thx so much
#Boss Queen is 100% right, thank you so much girllll!!!!!
To find the surface area of a cylinder, we need to calculate the areas of the two circular bases and the lateral surface area.
1. The area of a circle is given by the formula: A = πr^2, where A is the area and r is the radius.
The radius of the cylinder's base is 3x - 2cm, so the area of each circular base is: A_base = π(3x - 2)^2
2. The lateral surface area of a cylinder can be calculated using the formula: LSA = 2πrh, where LSA is the lateral surface area, r is the radius, and h is the height.
In this case, the height of the cylinder is x + 3cm, so the lateral surface area is: LSA = 2π(3x - 2)(x + 3)
3. Finally, to find the total surface area, we need to add the areas of the two bases and the lateral surface area:
Total surface area = 2A_base + LSA
= 2[π(3x - 2)^2] + 2π(3x - 2)(x + 3)
= 2π(3x - 2)^2 + 2π(3x - 2)(x + 3)
Therefore, the surface area of the cylinder is 2π(3x - 2)^2 + 2π(3x - 2)(x + 3).