solve the system of equations 4x - 3y= 8 2x+ 5y= 9
multiply the second equation by -2. Then add the equations.
solve the system of equations 4x - 3y= 8 2x+ 5y= 9 thanks for the hint but i think the answer is (1/2,2) or(2,1) if wrong please reply bobpursley and show work so ican understand
2x=5y=9 the equation is 2x+5y=-9
i believe the answer is (1/2,-2).
To solve the given system of equations:
4x - 3y = 8 ---(equation 1)
2x + 5y = 9 ---(equation 2)
There are a few different methods you can use, but I'll explain how to solve it using the method of substitution:
Step 1: Solve one equation for one variable in terms of the other variable. Let's solve equation 1 for x:
4x - 3y = 8
4x = 3y + 8
x = (3y + 8)/4
Step 2: Substitute the expression we found for x into the second equation:
2x + 5y = 9
2((3y + 8)/4) + 5y = 9
(3y + 8)/2 + 5y = 9
Multiply through by 2 to get rid of the fraction:
3y + 8 + 10y = 18
13y + 8 = 18
13y = 10
y = 10/13
Step 3: Substitute the value of y into the expression we found for x:
x = (3y + 8)/4
x = (3(10/13) + 8)/4
x = (30/13 + 8)/4
x = (30/13 + 104/13)/4
x = 134/13 ÷ 4
x = 134/13 × 1/4
x = 134/52
Simplify the fraction:
x = 67/26
So, the solution to the system of equations is x = 67/26 and y = 10/13.