The volume of a gas is 250 mL at 340.0 kPa pressure. What will the volume be when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant?
Is this Boyle's Law?
P1*V1=P2*V2
To determine the new volume of the gas when the pressure is reduced, we can use Boyle's Law. Boyle's Law states that the volume of a gas is inversely proportional to its pressure, assuming constant temperature.
Boyle's Law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure (340.0 kPa)
V1 = initial volume (250 mL)
P2 = final pressure (50.0 kPa)
V2 = final volume (which we need to find)
Rearranging the equation to solve for V2:
V2 = (P1 * V1) / P2
Substituting the given values:
V2 = (340.0 kPa * 250 mL) / 50.0 kPa
Calculating the new volume:
V2 = 1700 mL
Therefore, the volume of the gas will be 1700 mL when the pressure is reduced to 50.0 kPa, assuming the temperature remains constant.