A +1.4-nC point charge is placed at one corner of a square (1.8 m on a side), and a -2.5-nC charge is placed on the corner diagonally opposite. What is the magnitude of the electric field at either of the other two corners?
To find the magnitude of the electric field at one of the other two corners of the square, we can use the formula for the electric field due to a point charge:
Electric field (E) = (k * q) / r^2
where k is the Coulomb's constant (8.99 × 10^9 N m^2/C^2), q is the charge, and r is the distance between the charge and the point at which you want to calculate the electric field.
In this case, the charge at one corner is +1.4 nC, and the charge at the diagonally opposite corner is -2.5 nC.
Let's calculate the electric field at one of the corners:
- Distance (r) between the charge and the corner of interest = 1.8 m (because the distance between the corners is the side length of the square).
- Using the formula:
E = (k * q) / r^2
- Plugging in the values:
E = (8.99 × 10^9 N m^2/C^2 * 1.4 × 10^-9 C) / (1.8 m)^2
Now, calculate the value of E.