Suppose you tired to carry out a double-replacement reaction by mixing together equal volumes of a solution that contained dissolved NaF and a solution that contained dissolved NaCl. Would you expect a reaction, if so write the balanced chemical equation?
If those two substances were the only ones in the solution there will be no reaction. Reactions occur for one of just a few reasons.
1. A ppt is formed. Nothing insoluble here.
2. A gas is formed. No gas can be formed here.
3. A slightly ionized material is formed. Both NaCl and NaF are completely ionized.
4. A redox reaction occurs. There is nothing here to be "redoxed".
To determine whether a reaction would occur when mixing the solutions containing dissolved NaF and NaCl, we need to consider the solubility rules and the possibility for a double-replacement reaction.
The solubility rules state that most compounds containing sodium (Na+) and fluorine (F-) are soluble, while most compounds containing sodium (Na+) and chloride (Cl-) are also soluble. Therefore, both NaF and NaCl are soluble in water.
In a double-replacement reaction, the positive ions in the reactants exchange places to form new compounds. Since both NaF and NaCl are soluble, the reaction is unlikely to occur since no insoluble compound can be formed.
The balanced chemical equation for the reaction that would not occur is:
NaF (aq) + NaCl (aq) ⟶ No reaction
In this case, no reaction is expected, and the resulting solution would simply contain dissolved Na+ and Cl- ions.
Yes, we would expect a reaction to occur between sodium fluoride (NaF) and sodium chloride (NaCl) because they are both salts and can undergo a double-replacement reaction. The balanced chemical equation for the reaction can be written as:
NaF + NaCl → NaCl + NaF