What is the solution for 2x^2-7x>-3? (2 marks) (Show your work)
2x^2 - 7x + 3 > 0
(2x-1)(x-3) > 0
the roots of the equation are 1/2 and 3
Since the parabola opens up,
2x^2-7x > -3 when x is outside the interval between the roots:
x < 1/2 or x > 3
See
http://www.wolframalpha.com/input/?i=2x^2-7x%3E-3