A particular jet aircraft must reach a speed of 43 m/s in order to take-off. If the acceleration of the plane is 1329 m/s2, the minimum length of the runway is Answermeters
at 1329 m/s^2 it will take 43/1329 = 0.032 seconds to achieve takeoff speed.
Now that is some acceleration!!
You sure there's not a typo somewhere in there?
Anyway, once you have the correct takeoff time, just plug in the distance formula
s = 1/2 at^2
to find the required distance.
To find the minimum length of the runway, we need to use the kinematic equation that relates speed, acceleration, and distance:
v^2 = u^2 + 2as
where:
v = final velocity (43 m/s)
u = initial velocity (0 m/s, as the aircraft is at rest initially)
a = acceleration (1329 m/s^2)
s = distance
Rearranging the equation, we have:
s = (v^2 - u^2) / (2a)
Substituting the given values:
s = (43^2 - 0^2) / (2 * 1329)
s = (1849 - 0) / 2658
s = 1849 / 2658
s ≈ 0.694 meters
Therefore, the minimum length of the runway is approximately 0.694 meters.