A block and tackle with a velocity of 5 is used to raise a mass of 25kg through a vertical distance of 40cm at a steady rate,if the effort is equal to 60N,determine the distance moved by effort, work done by the effort in lifting the load and the loss of energy involved in operating the machine
A pulley system is used to lift a load of 300N. If the effort applied is 150N, determine the
mechanical advantage of the system.
To determine the distance moved by effort, we can use the equation:
Distance = Velocity × Time
We are given that the velocity is 5 and the load is raised at a steady rate, which implies the velocity is constant. Therefore, if we can find the time taken to raise the load, we can calculate the distance moved by effort.
To find the time, we can use the equation:
Work = Force × Distance
Given that the work done by the effort is equal to the force (60N) multiplied by the distance moved by effort, we can rearrange the equation to solve for the distance:
Distance = Work / Force
Now, let's find the time taken to raise the load. We can use the equation:
Work = Force × Distance
Given that the force is equal to 60N, and the distance is 40cm (which can be converted to meters by dividing by 100), we can calculate the work done by the effort.
Work = 60N × (40cm / 100) = 24 J (Joules)
Now, we can substitute the calculated work and the given force into the equation to find the distance moved by effort:
Distance = Work / Force = 24 J / 60N = 0.4 m or 40 cm
So, the distance moved by effort is 0.4 meters or 40 centimeters.
Next, let's find the work done by the effort in lifting the load. We already calculated it earlier when determining the time taken:
Work = 24 J
Finally, to find the loss of energy involved in operating the machine, we need to find the difference between the work done by the effort and the work done against gravity (lifting the load):
Loss of energy = Work - (Force × Distance)
Given that force equals 60N and distance equals 40cm (or 0.4m), we can calculate the loss of energy:
Loss of energy = 24 J - (60N × 0.4 m) = 24 J - 24 J = 0 J
Therefore, the loss of energy involved in operating the machine is 0 Joules.