What is the mass (in kilograms) of a cube of silver that measures 0.26m on each side
The density of silver is 10.5 g/cm3.What is the mass (in kilograms) of a cube of silver that measures 0.26m on each side
This may be the long way but I would
convert 0.26m to cm. That's 26 cm.
volume = 26cm x 26 cm x 26 cm = ? cc.
Then mass = volume x density
Then convert g to kg.
To find the mass of a cube of silver, we need to use its volume and density. The formula to calculate the volume of a cube is V = s^3, where s is the length of one side of the cube.
Given that the length of each side of the cube is 0.26m, we can find the volume:
V = (0.26m)^3
V = 0.0262m^3
Next, we need the density of silver. The density of silver is approximately 10,490 kilograms per cubic meter (kg/m^3).
Now we can calculate the mass (m) using the formula:
m = density * volume
m = 10,490 kg/m^3 * 0.0262m^3
m = 274.1388 kg
Therefore, the mass of the silver cube is approximately 274.14 kilograms.
To find the mass of the silver cube, we need to use its density and volume.
1. Determine the volume of the silver cube:
Since the cube measures 0.26m on each side, the volume can be calculated using the formula V = s^3, where s is the length of each side.
V = 0.26m * 0.26m * 0.26m
V = 0.017576m^3
2. Look up the density of silver:
The density of silver can be found in a reference material or an online source. Let's assume the density of silver is 10,500 kg/m^3.
3. Calculate the mass using the formula: mass = density * volume
mass = 10,500 kg/m^3 * 0.017576m^3
mass = 184.26 kg
Therefore, the mass of the silver cube is approximately 184.26 kilograms.