What is the specific heat capacity of aluminum if a 8.4 g sample increased 21.1 C upon the addition of 159.0 J? The units are J/(g ·K).

q=cpxMxT is the equation
my answer i got is 401.65 is that right bec i feel that's wrong

How in the world did you arrive at 401.65?

159.0J = 8.4g x sp.h. x 21.1
Solve for sp.h. = [159.0/(8.4*21.1)]

To determine the specific heat capacity (cp) of aluminum, we can follow these steps:

1. Identify the given values:
- Mass of the aluminum sample (m) = 8.4 g
- Temperature change (ΔT) = 21.1 °C
- Heat added (q) = 159.0 J

2. Since we are given the mass of the aluminum sample (m), we need to calculate the total heat energy transferred (Q). This can be done using the equation:
Q = m × cp × ΔT

3. Rearrange the equation to solve for cp:
cp = Q / (m × ΔT)

4. Substitute the values into the equation and calculate cp:
cp = 159.0 J / (8.4 g × 21.1 °C)

5. Be sure that all the units are consistent. Since the specific heat capacity is typically expressed in J/(g·K), you need to convert the temperature change from °C to K by adding 273.15:
cp = 159.0 J / (8.4 g × (21.1 + 273.15) K)

6. Calculate the value of cp:
cp ≈ 159.0 J / (8.4 g × 294.25 K)
cp ≈ 0.707 J/(g·K)

The correct specific heat capacity of aluminum, based on the given values, is approximately 0.707 J/(g·K). Therefore, your initial answer of 401.65 is incorrect.