Jose said all of the multiples of 8 are also multiples of 2? Manila said that all the multiples of 8 are also of 4. Who is correct?
Both are correct.
Multiples of 8:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80 . . .
They are all multiples of 2, 4, and 8.
To determine who is correct, let's take a closer look at the properties of multiples.
A multiple is a number obtained by multiplying another number by an integer (whole number). For example, the multiples of 8 are 8, 16, 24, 32, and so on, because they can all be obtained by multiplying 8 by different integers (1, 2, 3, 4, and so on).
Now, let's examine Jose's statement that all multiples of 8 are also multiples of 2. In this case, let's see if every number that is a multiple of 8 is also divisible by 2. If a number is divisible by 8, it means that it can be divided evenly (without remainder) by 8.
Let's test this with 16, which is a multiple of 8. If we divide 16 by 2, we get 8, which means 16 is divisible by 2. We can also test other multiples of 8, like 24, 32, and so on, and find that they are also divisible by 2. Therefore, Jose's statement is correct.
Now, let's examine Manila's statement that all multiples of 8 are also multiples of 4. We need to check if every number that is a multiple of 8 is also divisible by 4. Similar to the previous example, if a number is divisible by 8, it means it can be divided evenly (without remainder) by 8.
Let's test this with 16, which is a multiple of 8. If we divide 16 by 4, we get 4, which means 16 is divisible by 4. We can also test other multiples of 8, like 24, 32, and so on, and find that they are also divisible by 4. Hence, Manila's statement is correct as well.
Therefore, both Jose and Manila are correct. All multiples of 8 are also multiples of 2 and 4.