limit of x approaches -3. (2x^2 + 4x + 1)
To find the limit as x approaches -3 for the function (2x^2 + 4x + 1), we can substitute -3 into the function and see what value it approaches.
Plugging -3 into the function, we get:
(2(-3)^2 + 4(-3) + 1) = (2(9) - 12 + 1) = (18 - 12 + 1) = 7
Therefore, the limit of the function as x approaches -3 is 7.