What mass of water requires 1.89X10^8 joules of energy to heat from 15 degrees Celsius to 75 degree celsius?
The specific heat of water is 4190 J/kg degree celsius
To calculate the mass of water, we can use the formula:
Q = mcΔT
Where:
Q = Energy (in joules)
m = Mass of water (in kilograms)
c = Specific heat of water (in J/kg°C)
ΔT = Change in temperature (in °C)
Given:
Q = 1.89 × 10^8 J
c = 4190 J/kg°C
ΔT = 75°C - 15°C = 60°C
Now, we can rearrange the formula to solve for the mass:
m = Q / (c × ΔT)
Substituting the given values:
m = (1.89 × 10^8 J) / (4190 J/kg°C × 60°C)
m ≈ 902 kilograms
Therefore, the mass of water that requires 1.89 × 10^8 joules of energy to heat from 15°C to 75°C is approximately 902 kilograms.