arithmetic

Determining the first three terms of an ArithmetiC progressionof which the (a.)10th term is 31 and the 15th term is 49 (b.)7th term is 3 and 12th term is -3 (c.)5th term is 8 and the 11th term is -28 (d.)9th term is7+9x and d=2x,Show all calculations

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asked by Thandi Mstletoe
  1. (a)
    a+9d = 31
    a+14d = 49
    d = 18/5
    a = -7/5
    so, we have

    -7/5, 11/5, 29/5, ...

    (b) and (c) are just the same.

    (d)
    a+8d = a+16x = 7+9x
    a = 7-7x

    so,

    7-7x, 7-5x, 7-3x ...

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    posted by Steve

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