A lead fishing weight with a mass of 57g absorbs 146 cal of heat.
If its initial temperature is 48 C, what is its final temperature?
q = 146 cal = mass Pb x specific heat Pb x (Tfinal-Tinitial)
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To find the final temperature of the lead fishing weight, we can use the formula:
Q = mcΔT
Where:
Q = heat absorbed (in calories)
m = mass of the object (in grams)
c = specific heat capacity of the material (in cal/g°C)
ΔT = change in temperature (in °C)
In this case, the heat absorbed (Q) is given as 146 cal, the mass (m) is 57g, and the specific heat capacity (c) of lead is approximately 0.03 cal/g°C.
Rearranging the formula, we have:
ΔT = Q / (mc)
Plugging in the values, we get:
ΔT = 146 cal / (57g * 0.03 cal/g°C)
Calculating this, we find:
ΔT ≈ 85.09 °C
To find the final temperature, we need to add the change in temperature to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 48 °C + 85.09 °C
Calculating this, we find:
Final temperature ≈ 133.09 °C
Therefore, the final temperature of the lead fishing weight is approximately 133.09 °C.