how much heat is required to warm a 215 g cup of water from 21 degree Celsius to 85 degree Celsius?
Not sure what the formula is or how to set this up.
I know the specific heat formula is heat/mass x change in temperature.
Not sure if this applies to the question.
Please help. Thank you :)
It does.
heat = q = mass x specific heat x (Tfinal-Tinitial)
To find out how much heat is required to warm a cup of water from one temperature to another, you can use the formula for heat transfer:
Q = m * c * ΔT
where:
Q is the amount of heat transferred
m is the mass of the substance (water in this case)
c is the specific heat capacity of the substance (in this case, water)
ΔT is the change in temperature
First, let's gather the necessary information:
m (mass of water) = 215 g
c (specific heat capacity of water) = 4.184 J/g°C (this value is commonly used at room temperature)
ΔT (change in temperature) = final temperature - initial temperature = 85°C - 21°C = 64°C
Now, we can plug these values into the formula:
Q = 215 g * 4.184 J/g°C * 64°C
First, multiply the mass and the change in temperature:
Q = 13736.96 J/g
This gives you the total amount of heat energy required to warm the cup of water. The answer, in this case, is 13736.96 joules (J).