A bungee jumper jumps from a high bridge 100 m above a river. How fast does he fall after he has covered 60 m after jumping from the bridge? (Ignore air resistance in the fall.)

Well, if we're ignoring air resistance, then the only thing slowing down our bungee jumper will be the fear-induced sweat dripping from their forehead! But I digress.

To determine how fast our bungee jumper is falling after covering 60 meters, we can make use of the principles of motion. Let's assume that the jumper starts falling from rest.

Using the equation of motion: v² = u² + 2as,

v is the final velocity we're trying to find,
u is the initial velocity (which is 0 since the jumper starts from rest),
a is the acceleration due to gravity (approximated as 9.8 m/s²),
and s is the displacement (60 m in this case).

Substituting the values into the equation, we get:

v² = 0² + 2(9.8)(60)
v² = 0 + 1176
v = √1176
v ≈ 34.29 m/s

So, after covering 60 meters, our bungee jumper is falling at a speed of approximately 34.29 m/s. Just don't ask them to stick the landing with that kind of speed!

To find the speed at which the bungee jumper falls after covering 60 meters, we can use the equation for freefall:

vf^2 = vi^2 + 2ad

Where:
vf = final velocity (speed)
vi = initial velocity (initial speed)
a = acceleration due to gravity (approximately 9.8 m/s^2)
d = distance

Given the following information:
vi = 0 (since the jumper starts from rest)
a = 9.8 m/s^2
d = 60 m

Plugging in the values into the equation, we have:

vf^2 = 0^2 + 2*9.8*60

Simplifying further:

vf^2 = 1176
vf ≈ √1176
vf ≈ 34.29 m/s

Therefore, the bungee jumper falls at a speed of approximately 34.29 m/s after covering 60 meters.

To calculate the speed at which the bungee jumper is falling after covering a certain distance, we can use the principles of motion and gravitational acceleration.

The first step is to determine the time it takes for the jumper to cover the given distance. We can use the equation of motion:

s = ut + (1/2)at^2

Here, s is the distance covered (60 m), u is the initial velocity (which will be zero since the jumper starts from rest), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time taken.

Substituting the values into the equation:

60 = 0 + (1/2)(-9.8)t^2

Rearranging the equation:

t^2 = (2*60)/9.8

t^2 = 12.24

Taking the square root of both sides:

t ≈ 3.50 seconds

Now that we know the time taken, we can calculate the speed at that point. The formula to find speed is:

v = u + at

Substituting the values:

v = 0 + (-9.8)(3.50)

v ≈ -34.3 m/s

The negative sign indicates that the velocity is directed downward, as the jumper is falling. Therefore, the bungee jumper falls at a speed of approximately 34.3 m/s after covering a distance of 60 m.

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