A horse race has 13 entries. Assuming that there are no ties, what is the probability that the three horses owned by one person finish first, second, third

To calculate the probability of a specific outcome in horse racing, we need to first determine the total number of possible outcomes. In this case, there are 13 entries, so the total number of possible outcomes is 13!

Next, we need to find the number of favorable outcomes, which is the number of ways the three specific horses can finish in the first, second, and third positions. Since the order matters, there are 3! = 3 x 2 x 1 = 6 ways for the three horses to finish in the top three spots.

Therefore, the probability of the three horses owned by one person finishing first, second, and third is 6 divided by the total number of possible outcomes (13!).

To calculate the probability, we can use the formula:

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 6 / (13!)

Now we can evaluate this probability.

To find the probability that the three horses owned by one person finish first, second, and third in a horse race with 13 entries, we need to calculate the total number of possible outcomes and the number of favorable outcomes.

First, let's determine the total number of possible outcomes. Since there are 13 horses in the race, there are 13 possibilities for the horse that finishes first, 12 possibilities for the horse that finishes second (since one horse has already finished first), and 11 possibilities for the horse that finishes third (as two horses have already finished first and second). So the total number of possible outcomes is:

Total number of outcomes = 13 * 12 * 11.

Next, we need to determine the number of favorable outcomes, which is the number of ways the three horses owned by one person finish first, second, and third. Since all three horses are owned by the same person, there is only one way they can finish in that order.

Number of favorable outcomes = 1.

Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes:

Probability = Number of favorable outcomes / Total number of outcomes.

Probability = 1 / (13 * 12 * 11).

Therefore, the probability that the three horses owned by one person finish first, second, and third is 1 divided by the product of 13, 12, and 11.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

Assuming that the person does not have more than 3 horses in the race:

1/13 * 1/12 * 1/11 = ?

PsyDAG, your answer is wrong. The correct answer is

3/13 * 2/12 * 1/11 = 1/286