A 1100·kg elevator is attached to a cable whose tension is 10900·N. What is the magnitude of the elevator's acceleration?
m = 1100kg
F = 10900N
a = ? m/s^2
F = ma
a = F/m
a = (10900N)/(1100kg)
a = 9.91m/s^2
0.09
To find the magnitude of the elevator's acceleration, we can use Newton's second law of motion. The formula for Newton's second law is:
F = m * a
Where:
- F is the force acting on the object in Newtons (N)
- m is the mass of the object in kilograms (kg)
- a is the acceleration of the object in meters per second squared (m/s^2)
In this case, the force acting on the elevator is the tension in the cable, which is given as 10,900 N, and the mass of the elevator is given as 1,100 kg.
Plugging these values into the formula:
10,900 N = 1,100 kg * a
To solve for a, divide both sides of the equation by 1,100 kg:
10,900 N / 1,100 kg = a
Simplifying:
a ≈ 9.91 m/s^2
So, the magnitude of the elevator's acceleration is approximately 9.91 m/s^2.