An unknown substance with a mass of 300 g absorbs 1000 j of heat while undergoing a temperature increase of 15 degrees c. What is the specific heat of the unknown substance ?
To find the specific heat of the unknown substance, we can use the formula:
Q = mcΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
Q = 1000 J
m = 300 g
ΔT = 15°C
Plugging the given values into the formula, we have:
1000 J = (300 g)(c)(15°C)
Simplifying, we can divide both sides of the equation by (300 g)(15°C):
1000 J ÷ (300 g)(15°C) = c
Simplifying further:
1000 J ÷ (4500 g°C) = c
Now, let's calculate the specific heat of the unknown substance:
c = 0.222 J/g°C
Therefore, the specific heat of the unknown substance is 0.222 J/g°C.
To find the specific heat of the unknown substance, we need to use the equation:
Q = mcΔT
Where:
Q is the heat absorbed by the substance (in joules),
m is the mass of the substance (in grams),
c is the specific heat of the substance (in J/g°C), and
ΔT is the change in temperature of the substance (in °C).
Given:
Q = 1000 J
m = 300 g
ΔT = 15°C
We can rearrange the equation to solve for c:
c = Q / (m * ΔT)
Now, substitute the given values:
c = 1000 J / (300 g * 15°C)
First, convert the mass from grams to kilograms:
c = 1000 J / (0.3 kg * 15°C)
Simplifying further:
c = 1000 J / 4.5 kg°C
Finally, perform the division to find the specific heat:
c ≈ 222.22 J/kg°C
So, the specific heat of the unknown substance is approximately 222.22 J/kg°C.