Thallium(I) hydroxide is a strong base used in the synthesis of some organic compounds. Calculate the pH of a solution containing 2.13 g TlOH per liter.
Convert 2.13 g TlOH to moles. Divide moles by 1 liter to get the molar concentration in moles/liter or "M".
moles/L of TlOH = moles/L of OH- ions (since TlOH is a strong base). Calculate the pOH:
pOH = -log[OH-]
and
pH = 14 - pOH
i did this problem with 2.48 g and got 1.42 pH for OH- and 12.6 for H+
To calculate the pH of a solution containing Thallium(I) hydroxide (TlOH), we need to determine the concentration of hydroxide ions (OH-) in the solution first.
Step 1: Find the molar mass of TlOH.
The molar mass of Thallium (Tl) is 204.38 g/mol, and the molar mass of Hydroxide (OH) is 17.01 g/mol. Therefore, the molar mass of TlOH is:
Molar mass of TlOH = 204.38 g/mol + 17.01 g/mol = 221.39 g/mol
Step 2: Calculate the molarity of TlOH.
We know that the solution contains 2.13 g TlOH per liter. We can convert this to moles by dividing the mass by the molar mass:
Moles of TlOH = 2.13 g / 221.39 g/mol = 0.00962 mol
Since the molarity (M) is defined as moles of solute per liter of solution, the molarity of TlOH is:
Molarity of TlOH = 0.00962 mol / 1 L = 0.00962 M
Step 3: Determine the concentration of hydroxide ions (OH-).
Thallium(I) hydroxide is a strong base and dissociates completely in water. This means that each molecule of TlOH will produce one hydroxide ion (OH-).
Therefore, the concentration of hydroxide ions (OH-) is equal to the molarity of TlOH:
Concentration of OH- = 0.00962 M
Step 4: Calculate the pOH.
The pOH is calculated using the formula:
pOH = -log10[OH-]
pOH = -log10[0.00962] = 2.02
Step 5: Determine the pH.
The pH can be calculated using the formula:
pH = 14 - pOH
pH = 14 - 2.02 = 11.98
Therefore, the pH of the solution containing 2.13 g TlOH per liter is approximately 11.98.
To calculate the pH of a solution containing Thallium(I) hydroxide (TlOH), we need to find the concentration of hydroxide ions (OH-) in the solution.
First, let's determine the number of moles of TlOH in the solution:
1. Calculate the molar mass of TlOH:
Molar mass of Tl = 204.383 g/mol
Molar mass of H = 1.00784 g/mol
Molar mass of O = 15.999 g/mol
Molar mass of TlOH = 204.383 + 1.00784 + 15.999 = 221.39 g/mol
2. Convert the given mass (2.13 g) to moles:
Moles of TlOH = Mass / Molar mass
= 2.13 g / 221.39 g/mol
= 0.0096192 mol
Next, we need to find the concentration of OH- ions in the solution. Since TlOH is a strong base, it dissociates completely in water to give one Tl+ ion and one OH- ion.
3. The concentration of OH- ions is equal to the concentration of TlOH:
Concentration of OH- ions = Moles of TlOH / Volume of solution
The volume of the solution is given as 1 liter, so:
Concentration of OH- ions = 0.0096192 mol / 1 L
= 0.0096192 M
Now, we can calculate the pOH of the OH- ions:
4. pOH = -log10[OH-]
= -log10(0.0096192 M)
Using a calculator, we find that the pOH is approximately 2.02.
Since pH + pOH = 14 (at 25°C), we can calculate the pH:
5. pH = 14 - pOH
= 14 - 2.02
= 11.98
Therefore, the pH of the solution containing 2.13 g TlOH per liter is approximately 11.98.