a 1kg object moving east with a velocity of 10 m/s collides with a .50kg object that is at rest. neglecting friction, what is the momentum of the system? please show work
Momentum= 1*10=10Nt-sec
the at rest mass has zero momentum
To find the momentum of the system, we need to calculate the total momentum of both objects after the collision.
The formula for momentum is given by:
Momentum = Mass × Velocity
Given that the mass of the 1 kg object is 1 kg and its velocity is 10 m/s, the momentum of the 1 kg object is:
Momentum1 = Mass × Velocity = 1 kg × 10 m/s = 10 kg·m/s
Since the 0.50 kg object is initially at rest, its velocity is 0 m/s. Therefore, the momentum of the 0.50 kg object is:
Momentum2 = Mass × Velocity = 0.50 kg × 0 m/s = 0 kg·m/s
Since momentum is a vector quantity, we can determine the total momentum of the system by adding the individual momenta as vectors:
Total Momentum = Momentum1 + Momentum2
Total Momentum = 10 kg·m/s + 0 kg·m/s = 10 kg·m/s
Thus, the momentum of the system is 10 kg·m/s.
To find the momentum of the system, we need to calculate the momentum of each object individually and then add them together.
The momentum of an object is given by the formula:
Momentum = mass * velocity
For the first object (1kg) moving east with a velocity of 10 m/s,
Momentum = 1 kg * 10 m/s = 10 kg⋅m/s
For the second object (0.50kg) at rest,
Momentum = 0.50 kg * 0 m/s (since it is at rest) = 0 kg⋅m/s
Now, to find the momentum of the system, we add the individual momenta together:
Momentum of the system = 10 kg⋅m/s + 0 kg⋅m/s = 10 kg⋅m/s
So, the momentum of the system is 10 kg⋅m/s.