A 5.0ml sample of liquid requires 4.5 ml of a 0.093N NaOH solution. What is the titratable acidity of the liquid expressed as g/L Tartaric acid?

mL x N x mew = grams tartaric acid.

mew = milliequivalent weight of tartaric acid = molar mass/2 = ?
grams from above is in 5.00 mL. Convert that to g/L.

mew = HOOC-CHOH-CHOH-COOH/2

150 gr/mol /2 = 75gr/mol

4.50ml x .093N x 75 gr/mol = 31.4 grams of tartaric acid in the 5ml sample.

31.4gr /5.0 ml = x gr/1 liter

is this correct?

To calculate the titratable acidity of the liquid expressed as g/L Tartaric acid, we need to understand the concept of titration and the relationship between the volume of the NaOH solution used and the concentration of Tartaric acid.

Titratable acidity refers to the amount of acid present in a substance that can be neutralized by a base. In this case, we are using NaOH (Sodium Hydroxide) as the base to neutralize the acid present in the liquid.

Given:
- Volume of liquid sample = 5.0 ml
- Volume of 0.093N NaOH solution used = 4.5 ml

To find the concentration of Tartaric acid in the liquid, we can use the following equation:

(Concentration of NaOH) x (Volume of NaOH used) = (Concentration of Tartaric acid) x (Volume of Tartaric acid)

We know the concentration and volume of NaOH used, so we can rearrange the equation to solve for the concentration of Tartaric acid:

Concentration of Tartaric acid = (Concentration of NaOH) x (Volume of NaOH used) / (Volume of Tartaric acid)

First, we need to calculate the concentration of NaOH:

Concentration of NaOH = 0.093N

Next, we can substitute the values into the equation:

Concentration of Tartaric acid = (0.093N) x (4.5 ml) / (5.0 ml)

Now, let's calculate the concentration of Tartaric acid:

Concentration of Tartaric acid = (0.093) x (4.5) / (5.0) N

Concentration of Tartaric acid = 0.0837N

To convert the concentration from moles per liter (M) to grams per liter (g/L), we need to know the molar mass of Tartaric acid. The molar mass of Tartaric acid is approximately 150.09 g/mol.

Now, we can use the following conversion factor to convert the concentration from moles per liter (M) to grams per liter (g/L):

1 M of Tartaric acid = 150.09 g/L of Tartaric acid

Concentration of Tartaric acid (g/L) = Concentration of Tartaric acid (N) x Molar mass of Tartaric acid (g/mol)

Concentration of Tartaric acid (g/L) = 0.0837 N x 150.09 g/mol

Finally, let's calculate the titratable acidity:

Concentration of Tartaric acid (g/L) = 12.55 g/L

Therefore, the titratable acidity of the liquid expressed as g/L Tartaric acid is approximately 12.55 g/L.